2.2 Subspaces
A vector space inside a vector space
1ReadingΒΆ
Material related to this page, as well as additional exercises, can be found in ALA Ch. 2.2 and LAA 4.1.
2Learning ObjectivesΒΆ
By the end of this page, you should know:
- the definition of a subspace
- examples of (i) subspaces and (ii) subsets that are not subspaces
3Defining SubspacesΒΆ
Vector spaces arising in applications typically consist of an appropriate subset of vectors selected from a larger vector space. These vector spaces living βinsideβ of other vector spaces are called subspaces.
One simple way to check if a subset of a vector space is a subsapce:
- The set of all vectors of the form , because is not in this set.
- The non-negative orthant . For any . Hence, is not closed under scalar multiplication.
- The unit sphere because . In general, curved surfaces like the paraboloid are not subspaces. Think about connecting two points by a straight line and relate to the closure property.
Here, our base vector space is , the space of all doubly infinite signals .
The set that are zero for all indices except : if then is also zero for all indices not in for any .
The set of signals that sum to zero and are absolutely convergent, i.e., if and only if
To check this, we compute the sum of :
where we have used that , and
Note that we need the absolute convergence condition, i.e., that to split up the infinite sum above into two sums (check back on your Math 1400/1410 notes to see why!).
The following are easily verified to be subspaces of .
- The space of symmetric matrices, i.e. matrices satisfying for all . For example, re matrices of the form
The space of diagonal matrices, i.e., matrices with if .
The space of upper triangular matrices and the space of lower triangular matrices are both subspaces.
Here our base space is , the space of real-valued functions defined on the interval .
the space of polynomials (of degree at most ), defined over . The 0 function is in , and is a vector space contained in .
The spcae of all continuous functions defined on . Showing closure of this space relies on knowing that if and are continous, then so is for any , something you may have seen in Math 1400/1410.